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30(36/20)^2=x
We move all terms to the left:
30(36/20)^2-(x)=0
We add all the numbers together, and all the variables
-x+30(+36/20)^2=0
We add all the numbers together, and all the variables
-1x+30(+36/20)^2=0
We multiply all the terms by the denominator
-1x*20)^2+30(+36=0
Wy multiply elements
-20x^2+36=0
a = -20; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-20)·36
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{5}}{2*-20}=\frac{0-24\sqrt{5}}{-40} =-\frac{24\sqrt{5}}{-40} =-\frac{3\sqrt{5}}{-5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{5}}{2*-20}=\frac{0+24\sqrt{5}}{-40} =\frac{24\sqrt{5}}{-40} =\frac{3\sqrt{5}}{-5} $
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